{"id":4449,"date":"2023-03-21T12:02:18","date_gmt":"2023-03-21T10:02:18","guid":{"rendered":"http:\/\/www.zsvltava.cz\/fyzika\/?p=4449"},"modified":"2025-04-10T09:34:10","modified_gmt":"2025-04-10T07:34:10","slug":"priklad-s-cd-mereni-pro-9-rocnik","status":"publish","type":"post","link":"https:\/\/www.zsvltava.cz\/fyzika\/?p=4449","title":{"rendered":"M\u011b\u0159en\u00ed s CD"},"content":{"rendered":"<p>Va\u0161\u00edm \u00fakolem je pomoc\u00ed m\u011b\u0159en\u00ed a v\u00fdpo\u010dt\u016f zjistit:<\/p>\n<ol>\n<li>Jak\u00fd je objem hlin\u00edku v CD, pokud je tlou\u0161\u0165ka hlin\u00edkov\u00e9ho pl\u00e1tku 0,7 \u03bcm<\/li>\n<li>Kdybychom z hlin\u00edku v CD ud\u011blali kuli\u010dku. Jak\u00e9 by m\u011bla rozm\u011bry?<\/li>\n<li>Kolik CD m\u016f\u017ee vzniknout z 1 kg Al?<\/li>\n<li>Jak\u00e9 mno\u017estv\u00ed plastu je obsa\u017eeno v 1 CD?<\/li>\n<li>Jak\u00fd je pom\u011br mezi hmotnost\u00ed Al a plastu? Hustota hlin\u00edku je: 2,7 g.cm-3<\/li>\n<\/ol>\n<h2>Postup &#8211; n\u00e1pov\u011bda<\/h2>\n<p><strong>1. Kovov\u00fd disk m\u00e1 tvar v\u00e1lce. Je tedy pot\u0159eba zjistit objem. Tzn. zm\u011b\u0159it pr\u016fm\u011br disku (v\u00edcekr\u00e1t) a pou\u017e\u00edt polom\u011br k ur\u010den\u00ed objemu. (Objem cel\u00e9ho disku \u2013 otvor.)<\/strong><\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 21px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.zsvltava.cz\/fyzika\/wp-content\/ql-cache\/quicklatex.com-e1a9b5fb12e1fd8a8153fa8440d1d4c6_l3.png\" height=\"21\" width=\"108\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91; &#32;&#32;&#32;&#32;&#86;&#95;&#123;&#118;&aacute;&#108;&#99;&#101;&#125;&#32;&#61;&#32;&#92;&#112;&#105;&#32;&#114;&#94;&#50;&#32;&#104; &#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 23px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.zsvltava.cz\/fyzika\/wp-content\/ql-cache\/quicklatex.com-4c8ad25b414d04a9b6792d79033d9b66_l3.png\" height=\"23\" width=\"333\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91; &#32;&#32;&#32;&#32;&#86;&#95;&#123;&#118;&aacute;&#108;&#101;&#99;&#32;&#45;&#32;&#111;&#116;&#118;&#111;&#114;&#125;&#32;&#61;&#32;&#92;&#112;&#105;&#32;&#114;&#95;&#49;&#32;&#94;&#50;&#32;&#104;&#32;&#45;&#32;&#92;&#112;&#105;&#32;&#114;&#95;&#50;&#32;&#94;&#50;&#32;&#104;&#32;&#61;&#32;&#92;&#112;&#105;&#32;&#104;&#32;&#40;&#114;&#95;&#49;&#32;&#94;&#50;&#32;&#45;&#32;&#114;&#95;&#50;&#32;&#94;&#50;&#41; &#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p>kde h je tlou\u0161\u0165ka pl\u00e1tku 0,7 \u03bcm, r<sub>1<\/sub> je polom\u011br cel\u00e9ho CD a r<sub>2<\/sub> je polom\u011br otvoru.<\/p>\n<p>1 \u03bcm = 10<sup>-6<\/sup> m<br \/>\n1 \u03bcm = 10<sup>-4<\/sup> cm<br \/>\n1 \u03bcm = 10<sup>-3<\/sup> mm<\/p>\n<p><strong>2. Ur\u010dit polom\u011br ze vzorce pro v\u00fdpo\u010det objemu koule.<\/strong><\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 39px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.zsvltava.cz\/fyzika\/wp-content\/ql-cache\/quicklatex.com-103f54d72e33555248dfbc0a5fd782ab_l3.png\" height=\"39\" width=\"80\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91; &#32;&#32;&#32;&#86;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#52;&#125;&#123;&#51;&#125;&#32;&#92;&#112;&#105;&#32;&#114;&#94;&#51;&#32;&#92;&#92; &#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 45px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.zsvltava.cz\/fyzika\/wp-content\/ql-cache\/quicklatex.com-955985fc13c37cbb72c5e6eaacaf142b_l3.png\" height=\"45\" width=\"87\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91; &#32;&#32;&#32;&#114;&#32;&#61;&#32;&#92;&#115;&#113;&#114;&#116;&#91;&#51;&#93;&#123;&#92;&#102;&#114;&#97;&#99;&#123;&#51;&#125;&#123;&#52;&#125;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#86;&#125;&#123;&#92;&#112;&#105;&#125;&#125; &#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p><strong>3. Ur\u010d\u00edm hmotnost kovov\u00e9ho pl\u00e1tku.<\/strong><\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 17px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.zsvltava.cz\/fyzika\/wp-content\/ql-cache\/quicklatex.com-a84b0f3da95775eac4bf5842a5123292_l3.png\" height=\"17\" width=\"71\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91; &#109;&#32;&#61;&#32;&#92;&#114;&#104;&#111;&#32;&#46;&#32;&#86; &#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p>Zjist\u00edm, kolikr\u00e1t se v\u00fdsledn\u00e9 \u010d\u00edslo vejde do 1 kg.<\/p>\n<p><strong>4. Mno\u017estv\u00ed ur\u010duje objem nebo hmotnost.<\/strong><\/p>\n<p>Hmotnost CD zjist\u00edm pomoc\u00ed v\u00e1hy. Ode\u010dtu hmotnost kovu a z\u00edsk\u00e1m hmotnost plastu. <\/p>\n<p>Objem vypo\u010d\u00edt\u00e1m stejn\u011b jako disk u 1). S t\u00edm rozd\u00edlem, \u017ee r<sub>1<\/sub> a r<sub>2<\/sub> se t\u00fdkaj\u00ed plastu a h je tlou\u0161\u0165ka CD. Vzore\u010dek z\u016fst\u00e1v\u00e1 stejn\u00fd.<\/p>\n<p><strong>5. D\u00e1m do pom\u011bru (pom\u011br to je d\u011bleno = zlomek) hmotnost plastu a kovov\u00e9ho pl\u00e1tku a objem.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Va\u0161\u00edm \u00fakolem je pomoc\u00ed m\u011b\u0159en\u00ed a v\u00fdpo\u010dt\u016f zjistit: Jak\u00fd je objem hlin\u00edku v CD, pokud je tlou\u0161\u0165ka hlin\u00edkov\u00e9ho pl\u00e1tku 0,7 \u03bcm Kdybychom z hlin\u00edku v &#8230;. <\/p>\n","protected":false},"author":1,"featured_media":2212,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[49],"tags":[26,23],"class_list":["post-4449","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-priklady-pro-9-rocnik","tag-mereni","tag-reseny-priklad"],"_links":{"self":[{"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=\/wp\/v2\/posts\/4449","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=4449"}],"version-history":[{"count":0,"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=\/wp\/v2\/posts\/4449\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=\/wp\/v2\/media\/2212"}],"wp:attachment":[{"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=4449"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=4449"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.zsvltava.cz\/fyzika\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=4449"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}